STAT 400

Wed. January 29th, 2020


Sample Space & Events

In our example of a coin flip, where S={H,T}S=\{H,T\}, we can list out all possible events (all subsets of SS):

We can do the same with our die roll example, S={1,2,3,4,5,6}S=\{1,2,3,4,5,6\}:

All of these events can be assigned probability values, as we previously discussed.

The key thing to remember about probability values is that they represents frequency over the long run – in other words, it’s the average amount of times that an event will occur if an experiment is repeated many times.


Operations on Events

What is the probability that…

  1. …event AA doesn’t happen?
  2. both event AA and event BB happen?
  3. either event AA or BB happens?

These questions represent new events that are generated from information about other events.

Definition 1. AA' or ACA^C is called the complement of AA – the event where AA doesn’t happen.

Definition 2. ABA\cap B is called the intersection of AA and BB – the event where both AA and BB happen.

Definition 3. ABA\cup B is called the union of AA and BB – the event where either AA or BB happens.

Thus our three questions can be represented by P(A)P(A'), P(AB)P(A\cap B), and P(AB)P(A\cup B).

Because these operations give new events, we can chain multiple of them together: P(ABC)P(A\cap B\cap C) is the probability that AA, BB, and CC all occur.


Mutually Exclusive/Disjoint Events

Definition. When AB=A\cap B=\empty, AA and BB are said to be mutually exclusive (or disjoint) events. This implies that it is not possible for AA and BB to both occur in a given experiment.


Properties of Probability

Axioms of Probability

  1. P(A)0P(A)\ge 0 for all events AA.
  2. P(S)=1P(S)=1 for all sample spaces SS.
  3. If A1,A2,...A_1,A_2,... is an infinite sequence of disjoint events, then P(A1A2...)=i=1P(Ai)P(A_1\cup A_2\cup ...)=\sum_{i=1}^\infin P(A_i).

We can derive all other properties of probability from these three axioms.

Properties

  1. P()=0P(\empty)=0.
  2. If A1,A2...AnA_1,A_2...A_n is a finite sequence of disjoint events, then P(A1A2...An)=i=1nP(Ai)P(A_1\cup A_2\cup ...\cup A_n)=\sum_{i=1}^n P(A_i). (Finite version of 3rd axiom)
  3. P(A)+P(A)=1P(A)+P(A')=1.
    • AA=A\cap A'=\empty
    • AA=SA\cup A'=S
  4. P(A)1P(A) \le 1.
  5. P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B). (You need to subtract away the probability of events in AA AND BB so they don’t get double counted)
  6. P(ABC)=P(A)+P(B)+P(C)P(AB)P(BC)P(AC)+P(ABC)P(A\cup B\cup C)=P(A)+P(B)+P(C)-P(A\cap B)-P(B\cap C)-P(A\cap C)+P(A\cap B\cap C). (Same reasoning as above)